9

I'm on Debian-like OS.

Directory /var/lib/tor/keys/ contains secret_id_key and secret_onion_key RSA keys.

Would my relay work the same with 5Mb/s of bandwidth if I remove these keys each reboot, simply by /etc/rc.local ?

rm /var/lib/tor/keys/*
service tor restart

Say, I will start the relay fresh each time I boot. Am I losing any bounties from network like guard, etc...?

Will my bandwidth been used in the past be the same? E.g. When rebooting everyday. Or does warming-up of a new relay required more than 7 days?

Should I clean anything else?

Improve this question
3
  • "Or warming-up of new relay required more than 7 days?" I'm not sure what this should say, so I did not mess with it.
    – bastik
    Commented Oct 13, 2013 at 16:42
  • "Warming-up" means pass all of bandwidth's and guard's test embedded into Tor code.
    – polar bear on the white snow
    Commented Oct 26, 2013 at 13:14
  • Thanks for the explanation, I modified the question in regards to the meaning of that part.
    – bastik
    Commented Oct 26, 2013 at 14:06

1 Answer 1

Reset to default
8

The blog post »The lifecycle of a new relay« is helpful for your question:

A new relay, assuming it is reliable and has plenty of bandwidth, goes through four phases: the unmeasured phase (days 0-3) where it gets roughly no use, the remote-measurement phase (days 3-8) where load starts to increase, the ramp-up guard phase (days 8-68) where load counterintuitively drops and then rises higher, and the steady-state guard phase (days 68+).

So if you reboot every day and remove the keys on this basis your relay is a new relay after every reboot. So initially you will see a low amount of traffic. While you can do some steps to improve this, I guess this relay will not be very helpful for the network as a whole.

Furthermore there is quite a good chance that somebody notices the high rate of key rotation. I guess this will raise some questions and maybe lead to the fact that some people will distrust your relay.

Improve this answer

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .