I'm trying to sign up for Twitter on Tor, but whenever I do, I'm asked to give out a phone number for verification - which would render Tor useless as they would see my location.

No matter what, there is no link to skip the phone verification.

It loads in IE, and the link has a URL, but using it in Tor redirects you back to the phone verification page!

I have searched everywhere for an answer to this, and nothing works.

This has been a problem for months, and I figured Tor would've found a way around it by now.

Just what are you supposed to do?

  • 2
    Twitter are able to tell that your traffic is coming from a Tor exit node - all the exit node IP addresses are publicly available. They presumably don't want Tor users creating unverifiable accounts, so are adding the phone verification requisite. You could attempt to use a VPN in conjunction with Tor - or a VPN by itself - and see if you have any further luck. I suspect trying to contact Twitter would fall on deaf ears... Mar 21 '16 at 15:57
  • It's ridiculous. It really is. So why does Twitter work on Android through Orbot? Would I not be able to to use an android emulator and then run Orbot? And how do I know the VPN isn't a honeypot? Mar 21 '16 at 16:01
  • you can use get a burner number app on your phone which will givea fake number but i havent been able to get it cause it requires java
    – user14279
    Sep 10 '16 at 4:11
  • I just tried this with email verification instead of mobile number with Tor and it didn't work. It said I was breaking Twitter rules...
    – Anonymous
    Nov 26 '19 at 16:56

Alternatively if you are willing to spend more money, you can buy a burner phone with it's own sim card and after registration, throw it away.

However if currently (or in the future for the other people reading answer) you are from places where buying sim cards requires registration with your identity, government agencies can still track you down. That will also depend on your threat model if it includes these adversarial agencies or not.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.